Ln(t^2/2)=1

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Solution for Ln(t^2/2)=1 equation: 


D( t )

(t^2)/2 <= 0

(t^2)/2 <= 0

(t^2)/2 <= 0

1/2*t^2 <= 0

1/2*t^2 <= 0 // : 1/2

t^2 <= 0/1/2

t^2 <= 0

t in <0:0>

t in (-oo:0) U (0:+oo)

ln((t^2)/2) = 1 // - 1

ln((t^2)/2)-1 = 0

ln((t^2)/2)-1 = 0 // + 1

ln((t^2)/2) = 1

ln((t^2)/2) = ln(e^1)

(t^2)/2 = e^1

(t^2)/2-e^1 = 0

1/2*t^2 = e // : 1/2

t^2 = 2*e

t^2 = 2*e // ^ 1/2

abs(t) = 2^(1/2)*e^(1/2)

t = 2^(1/2)*e^(1/2) or t = -(2^(1/2)*e^(1/2))

t in { 2^(1/2)*e^(1/2), -(2^(1/2)*e^(1/2)) }

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